I am writing this post so that I can hopefully save myself time in the future from trying to track down this little snippet that will take the incoming XML to an XsltListViewWebPart and render it out. This is the snippet:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
  <xsl:template match="/">
    <xmp><xsl:copy-of select="*"/></xmp>
  </xsl:template>
</xsl:stylesheet>

This snippet comes from a community content comment on MSDN: http://msdn.microsoft.com/en-us/library/ff602042.aspx.